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4t^2/3=15-17^2/3
We move all terms to the left:
4t^2/3-(15-17^2/3)=0
We get rid of parentheses
4t^2/3-15+17^2/3=0
We multiply all the terms by the denominator
4t^2-15*3+17^2=0
We add all the numbers together, and all the variables
4t^2+244=0
a = 4; b = 0; c = +244;
Δ = b2-4ac
Δ = 02-4·4·244
Δ = -3904
Delta is less than zero, so there is no solution for the equation
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